projectile motion equations time of flight

The acceleration in the vertical motion of the particle in projectile is just due to acceleration due to gravity: There is no acceleration in the horizontal motion of the particle moving in projectile. The x components and y components of the initial velocity can be expressed as:Īccelerations in the horizontal and vertical motions of the particle moving in projectile can be expressed as: Along y-axis: The particle is moving with a uniform acceleration but varying velocity which is responsible for the vertical (downwards) motion of the particle. Along the x-axis: along x-axis velocity is uniform which is responsible for the horizontal (forward) motion of the particle.Ģ. In a Projectile Motion, there are always two simultaneous independent rectilinear motions happening:ġ. Let us consider a ball projected at an angle θ with respect to the horizontal x-axis with the initial velocity u as shown below: If the ground from which the projectile is launched is level, the time of flight only depends on the initial velocity v0, the launch angle, and the. Since, there is no acceleration in x direction so it can be simply calculated using equation $s = ut$, where we have to put u the horizontal velocity and t the time of flight.

Hence, calculate time to reach maximum height by using equation $v = u + at$ and taking v = 0 for maximum height.Īnd the horizontal range is the displacement of the projectile in x direction. Time of flight is the total time taken to complete the projectile motion, it will be double the time taken to reach the maximum height. Where, u = initial velocity, v = final velocity, s = displacement, a = acceleration and t = time.

Hint: Consider the projectile motion to be the sum of two rectilinear motion in x-axis and y-axis.Īpply equations of motion separately in these two motions:

Projectile motion equations time of flight